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CBSE ANNUAL PAPER - 1999
SCIENCE
(THEORY)
(SET-I)
Time Allowed : 3 Hours
Maximum Marks : 75
General Instructions :
(i) All questions
are compulsory.
(ii) Marks for each
question are indicated against it.
(iii)
Question numbers 1 to 10 are very short answer
type questions, carrying 1 mark each to be
answered in one word or maximum in one
sentence.
(iv)
Question numbers 11 to 20 are short answer type
questions. Carrying 2 marks. answer may not
normally exceed 40 words each.
(v)
Question numbers 21 to 30 are short answer type
questions of 3 marks each. Answer may not
normally exceed 60 words each.
(vi)
Questions numbers 31 to 33 are long answer type
questions, carrying 5 marks each, which should
not be answered in more than 100 words
each.
(vii)
Please write down the serial number of the
question before attempting it.
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Q. 1 |
Name the orbit of the
satellites that help in satellite
communication. |
Ans. |
"Geo - stationary
orbit". |
Q. 2. |
A torch cell converts one
form of energy into another form. Name these two
forms. |
Ans. |
Chemical energy to electrical energy.
|
Q.3. |
Name the process that forms
the basis of a hydrogen
bomb. |
Ans. |
"Nuclear fusion.' |
Q. 4. |
How does the conductivity
of a semi - conductor change when certain
impurities are added to
it? |
Ans. |
Conductivity, that is ability to conduct
electricity, or a semi conductor increases
considerably when certain impurities are added
to it. |
Q.5. |
Name any two constituents
of petroleum which are not used as
fuel. |
Ans. |
Asphalt, Grease, mobile oil.
|
Q. 6. |
Why does common salt become
moist in rainy season? |
Ans. |
Common
salt contains some amount of MgCl2(Magnesium Chloride)
which absorbs moisture from air in rainy season,
when air has the maximum moisture in it, and
becomes moist. |
Q. 7. |
Which property of diamond
makes it a suitable material for high precision
thermometers ? |
Ans. |
Diamond
is very sensitive to heat rays.
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Q.8. |
Name the Vitamin which gets
oxidised when cut fruits are left exposed to air
for a long time. |
Ans. |
Vitamin
-C. |
Q. 9. |
In a good chain comprising
lion, grass and dear, which will (i) transfer
the maximum amount of energy (ii) receive
minimum amount of
energy. |
Ans. |
(i)
Maximum amount of energy will be transferred by
grass. (ii) Minimum amount
of energy will be received by lion.
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Q.10. |
Which of the following is a
true solution ? Vinegar in water, Aluminum paints, Blood,
Muddy water. |
Ans. |
Vinegar
in water. |
Q.11. |
The lungs perform 2.4 J of
work during each expansion. How many times per
minute do they expand if their power is 2 watts
? |
Ans. |
Work
done by lungs in 1 expansion = 2.4 J
Power of lungs = 2 w
Power = Work / Time
Time = Work / Power
Time taken by lungs
in expansion = 2.4 2.4 J /2 W = 1.2 Sec.
NO. of expansions in
1 min. or 60 sec.
= 60/1.2 = 50 Expan.
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Q.12. |
Cadmium rods play an
important role in a nuclear reactor. What
happens (i) When they are completely inserted
into nuclear fuel, and (ii) when they are slowly
withdrawn from nuclear
fuel. |
Ans. |
(i)
Nuclear fission is stopped when the cadmium rods
are completely inserted into the nuclear fuel as
the cadmium rods absorb all the neutrons
responsible for fission reaction.
(ii)
When cadmium rods are withdrawn slowly from the
nuclear fuel, the fission of nuclear fuel starts
and goes on increasing as the rods are withdrawn
because neutrons will be available for fission
reaction.
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Q.13. |
Mention any two differences
between a planet and a
star. |
Ans. |
Star |
Planet |
1. Star
has its own light to illuminate. |
1.
Planet does not illuminates. They only shine in
the light of star. |
2.
Stars move around its axis and has its own
planets system. |
2.
Planets revolve around the star as well as
around its axis. They have their satellite
system. |
3. Size
and mass of star is very larger than a planet.
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3. Size
and mass of a planet is lesser than a star.
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4.
Stars are made up of hydrogen or helium gases.
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4.
Planets are made up of dust particles or heavier
particles.
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Q.14. |
A compound which is
prepared from gypsum has the property of
hardening when mixed with proper quantity or
water. Identify the compound. Write the chemical
equation of its preparation. Mention one
important use of the
compound. |
Ans. |
Identification -
The given compound is Plaster of paris (
hemihydrated calcium sulphate) ( (CaSO4)2.H2O) Preparation - It is prepared by
heating gypsum.
Use - It is used in
surgery to maintain joints in a fixed position.
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Q.15. |
Which category of compounds
is formed when one hydrogen atom of an alkane
molelcule is replaced by a hydroxy1 group ? Name
the functional groups is the following
compounds.
|
Ans. |
'Alcohol' is formed when one hydrogen atom
an alkane molecule is replaced by a hydroxyl
group (-OH).
O O
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(i) In compound R -
C - OH - C - OH. or - COOH is the functional
group naming Carboxyl group.
O O
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(ii) In compound R -
C - O - R', - C - O or - COO. is the functional
group naming ester group. |
Q.16. |
How is the polar nature of
water responsible for dissolving (i) Sodium
chloride (ii) Sugar
? |
Ans. |
Polar
Nature of water - Water molecule is made up of
one oxygen atom and two hydrogen atoms. Oxygen
atom end has some negative charge (d - ) while hydrogen
atoms end has some positive charge (d + ) thus water
molecule has two ends with different charges.
(ii)
Sodium Chloride is an electrovalent compound and
Na+ and CL ions
attach with both ends of unlike charged ends of
water molecule resulting the Nacl be dissolved
in water due to weakening of ionic bond.
(iii)
Sugar is a covalent compound. Hydrogen atoms of
water molecule can chemically bind loosely with
the strongly electro negative atoms of covalent
compound by hydrogen bonds and thus sugar is
dissolved in water. |
Q.17. |
Give an example of a food
chain consisting of four organisms at different
trophic levels. Give the scientific term used to
indicate the first and third trophic
level. |
Ans. |
Food
chain : Grain plants ----
Rat --- Snake ---- kite
I II III IV
First trophic
level - At first trophic level grain
plants are present which synthesise the fod and
trap solar energy. Organisms at this level are
called producer.
Second Trophic
level - Organisms present at IInd
trophic level is Rat which feed on grain plants
i.e. rat gets its food from plants so, it is
called herbivore or first consumer.
Third trophic
level - Snake is present at IIIrd
trophic level which is IInd consumer and
consumers rat as food. Organisms at this level
are called carnivores. |
Q.18. |
What is biological fixation
? How is it different from nitrification ? Give
an example of organism involved in each of
these. |
Ans. |
Biological Fixation - The conversion of
nitrogen gas of the atmosphere into nitrogen
compound nitrates, easily usable form of
nitrogen for plants by the action of bacteria
and algae, is called biological fixation. e.g.
Rhizobium bacteria present in root nodules of
leguminous plants. Nitrification - It is one step of nitrogen
cycle in nature. In this step ammonia is
converted first into nitrites and then in
nitrates.
Nitrosomonas - bacteria convert ammonia
into nitrites.
Nitrobacter - bacteria convert nitrites
into nitrates. These two bacteria are called
nitrifying bacteria.
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Q.19. |
Differentiate between
arithmatic progression and geometric progression
in terms of food and
population. |
Ans. |
1. Food
Production - Food production increases
in arithmatic progression. In arithmatic
progression the factor simply add up, so the
increase is less. Food Production -
(i) Arithmatic progression -
2--4--6--8--10--12--14.....
2. Geometric
Progression - In the geometric
progression the factor go on multiplying, So the
increase is very rapid. Population increases in
geometrical progression.
(ii) Population
--2--4---8--16---32--64.....
(Geometric
Progression )
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Q.20. |
What is immunity ? Name the
diseases against which DPT vaccine acts as a
preventive
measure. |
Ans. |
Immunity - The
resistance power of the body against diseases is
called immunity, it is natural and created
(artificial) . D.P.T. Vaccine prevents the body
against following three diseases. D - Diphtheria
P- Pertusis (
whooping cough)
T-Tetanus.
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Q.21. |
A 100 watt electric bulb is
lighted for 2 hours every day and five 40 watt
tubes are lighted for four every day. Calculate
(i) the energy consumed for 60 days and (ii) the
cost of electricity consumed at the rate of Rs.
1.50 per K.wh. |
Ans. |
Power
of bulb = 100w Time of use = 2
hours perday
Electricity consumed
by bulb perday = 100X2 / 1000 kwh.
Electricity consumed
by bulb in 60 days = 100 X 2 / 1000 X 60 /1 KWh
= 12 Kwh
Power of tube = 40 w
Time of use = 4 hr.
Electricity consumed
by 5 tubes per day = 40 X 5 X 4 /1000 kwh
Electricity consumed
by 5 tubes in 60 days = 40 X 5 X 4 / 1000 X 60/1
Kwh = 48 kwh
Total consumption of
electricity in 60 days = 12+48 = 60 kwh
Cost = 60 x 15 = Rs.
90.00 |
Q.22. |
Describe the sequence of
changes that would take place if all the
hydrogen present in the sun is converted to
helium. |
Ans. |
If all
the hydrogen of the sun converts into helium
then the following changes will occur.
(i) The
fusion reaction in the core would stop and
pressure in core would drop which would make the
sun core begin to contract under its own
gravity.
(ii) In
the outer shall hydrogen would continue to fuse
and will liberate energy. The shell would begin
expand, increasing its surface area. Intensity
of radiated energy would also be reduced, its
colour would begin to appear red. This stage is
called Red Giant phase.
(iii)
It outer shell would continue expanding and
would engulf the sun's planets, ultimately its
expanding shall would be lost.
(iv)
Its cost left behind would gradually condense
into an extremely dense ball of matter. Due to
high temperature and pressure helium of its core
would begin fuse into higher elements like
carbon. The energy liberated thus make the core
to glow. This glowing core is called white Dwarf
Star. As long as helium lasts the core would
convert into a dense lump. |
Q.23. |
Mass of the earth is
optimum to facilitate existence of life on it.
What would have happened if the earth had less
mass than at
present. |
Ans. |
Mass of
the earth is optimum to facilitate existence of
life on it. If the mass of earth had less than
at present then the following happenings could
be happened. (i) It
would have contained less amount of radio active
elements which in turn would have produced less
heat which could not be able for differentiation
of earth and no atmosphere would had formed.
(ii)
The earth kiln would not have fired to release
water vapours from hydrated minerals hence
formation of oceans - the bed for originating
primitive life, could not be happened.
(iii)
The core and mantle would not have formed which
release energy and which make the earth dynamic
through volcano eruptions, earthquakes,
formation of new rocks etc.
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Q.24. |
List the characteristics
which define the orbit of a satellite. Show
their position in a diagram. When is a satellite
is said to be in a sun synchronous orbit
? |
Ans. |
To
define an orbit of earth a satellite following
characteristics are taken in to consideration :
1. Apogee : It is the
farthest point on orbit of a satellite from the
earth.
2. Perigee :
It is the nearest point on the orbit of a
satellite from the earth.
3. Angle of
Inclination : It is the angle of
inclination of an orbit i.e. the angle between
orbit and the equator.
Sun synchronous
orbit - When the orbit of a satellite
is such that the satellite passes over a
particular latitude at approximately the same
local time. In other words, the position of the
sun with respect to a point on earth remains
approximately the same as the satellite passes
over it. OR we can say that the satellite in
this orbit always laces the sun.
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Q.25. |
Name the main constituents
of liquefied petroleum gas. Why is this gas
considered a better domestic fuel than others ?
(Give any four points) Give the calorific value
of LPG. |
Ans. |
The
main constituents of LPG are butane, isooctane,
propane and a very small amount of ethane.
LPG is
an ideal fuel because - (i) IT has high
calorific value i.e. approximately 55 KJ/g.
(ii) It's ogmotopm
temperature is proper.
(iii)
It does not produces smoke, harmful gases on
burning i.e. does not produce pollution.
(iv) It does not
leave solid residue behind as ash.
(v) It does not
blaken the utensils.
(vi) It's combustion
is regualr and moderate.
(vii) It's
transportation and storage is easy.
Calorific value of
LPG is 55 K.J./g. |
Q.26. |
Explain how the following
metals are obtained from their compounds by the
reduction process. (a) Metal X which is low in the reactivity
series.
(b) Metal Y which is in the middle of the
series.
(c) Metal Z which is high up in the
reactivity series.
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Ans. |
(a) Metal X -
Metal ! x is low in the reactivity series i.e.
it is very less reactive metal, so it can be
obtained by direct heating in air.
(b) Metal Y -
Metal Y is the middle of the series, it
an be obtained by heating with a reducing agent
like carbon or highly reactive metals like Na,
Ca, Al.
(c) Metal Z -
Metal Z is high up in the reactivity series. It
can be obtained by electrolytic reduction.
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Q.27. |
What are thermosetting
polymers ? Give two examples. Why can they be
not processed again
? |
Ans. |
Thermosetting plastics : It is the plastic
which do not soften on heating and can not be
remolded on heating in the desired shape.
Example : Bakelite,
Melamine.
Can't be processed
again - Thermosetting plastics are the
polymers which contain long chain of monomers
which are cross linked with each other.This
linkage prevents the displacement of individual
chain on being heated. Thus thermosetting
plastics do not suffer change in shape once they
have been set. |
Q.28. |
Describe with the help of a
flow diagram the transfer of energy from sun to
top carnivores. |
Ans. |
The
source of energy on earth is the only sun. Only
green plants are capable to trap the solar
energy coming on earth. Only 1 % of the total
coming energy in trapped by the green plants
during photosynthesis and converted into
chemical energy started in the food while the
rest of the energy is radiated back into the
environment. At each
tropic level 10 % of the obtained energy is
passed on to the next. Tropic level and 90 % of
that obtained energy is utilized at that very
level. This utilized energy is lost to
environment in the form of heat energy during
its metabolic activities. In this way it goes on
decreasing at each level and as result very less
energy is obtained by the last tropic level.
Suppose 1000 J of energy comes to earth then how
much energy will be available at different
tropic levels of a food chain, has been shown in
the following diagram :
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Q.29. |
A doctor examined a child
below the age of five years and found cracks and
scaly skin apart from wasting of muscles. Name
the disease the child is suffering from. Mention
two causes of it s occurrence. What diet should
be given to over come this
disease. |
Ans. |
The
symptoms, (i) cracks and scaly skin (ii) loss of
muscles in a child below the age of 5 years, are
the symptoms of Marasmus. causes of marasmus -
(i)
Weanation of children from Protein in rich
breast milk.
(ii)
Diet of child deficient in proteins and
carbohydrates due to poverty or lack of
education.
Remedies - (i) By
giving a sufficient protein and carbohydrates
rich diet such as a combination of wheat, gram,
peanuts, soyabean and jaggery.
(ii)
The diet should contain animal protein. Child
should be given a sufficient amount of milk,
curd, egg or cheese with carbohydrates.
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Q.30. |
Distinguish between
bactericidal and bacteriostatic methods of food
preservation. Give one example each of a food
material preserved by these
methods. |
Ans. |
Bactericidal
Method : In bactericidal method food is
preserved by killing the bacteria ( microbes).
Example
: Canning, cooking are the bactericidal methods.
jam, jelly boiling of milk are the food material
preserved by this method.
Bacteriostatic
Method :- In bacteriostatic method food
is preserved by checking the actives of
bacteria, enzymes. In this method enzyme and
microbes are made inactive or is stopped their
growth.
Example
: Dehydration, salting, pickling etc. are the
bacteriostatic methods. Mango pickle, Murata,
Leafy vegetables are preserved by this method.
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Q.31. |
Explain the working of four
- stroke engine using petrol as fuel. Draw a
neat labeled diagram of the ignition
stage. |
Ans.
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Working : Its
working can be explained with the help of five
following stages of its working : (a) Intake
Stroke : As shown in the fig (a) piston
moves outward the mixture of fuel and air enters
the cylinder through in-take value.
(b) Compression : Now piston moves
inside and the fuel + air mixture is compressed,
as shown in fig.
(c) Ignition :
As the mixture of fuel and air is compressed
fully, the spark plug produces an electric spark
which ignites the fuel.
(d) Expansion
: Hot vapours of gases on ignition expand and
push the piston outside which make the crank to
move. This is power stroke of the engine.
(e) Exhaust :-
In this stroke burnt gases as smoke is exhausted
through exhaust value.
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Q.32. |
Name the chief impurity
present in iron ore. What are the two
requirements to obtain iron from its ore. Draw a
labelled diagram of a blast furnace. State the
main reactions that take place in the blast
finance. Write the chemical equations
involved. |
Ans. |
The chief impurity
- Sand i.e. silicon dioxide (SiO2 ) is the chief
impurity present in iron ore.
Requirement - (i)
A suitable reducing agent to reduce iron oxide
to iron. Carbon monoxide (CO) is the reducing
agent which is obtained by burning of coke in an
insufficient supply of air in the blast furnace.
(ii)
Suitable solvent to dissolve ( remove ) silicon
dioxide (sand). Silicon dioxide is separated
using molten calcium oxide(CaO). It is obtained
by heating of lime stone CaCo3) in the best furnace.
Ore
: Most of the iron is obtained from the ore
Hematite and magnetite which are iron oxides.
(Fe2O3)
Structure of
furnace : It is a big furnace smaller
at the bottom, widens in the middle and again
narrow at the top. Finely frinded concentrated
ore, sand (SiO2)
lime stone (CaCo3) and coke is mixed together and
furnace is charged by this mixture from the top
in a regulated manner. Once started the furnace
can continue up to 5 years.
Process : Process
is completed in to following steps :
(I) Lime stone
(CaCo3 )
dissociate because of intense heat in the
furnace.
CaCO3
--------------- CaO + CO2
(ii)
Thus formed CaO removes the sand in the form of
calcium silicate which floats over the molten
iron at the bottom of the furnace.
CaO = Sio2 -- CaSiO3
Calcium Silicate
(slag)
(iii)
Reduction of iron oxide occurs by the CO formed
by heating of coke in insufficient supply of
oxygen. Thus molten iron is obtained at the
bottom of the furnace.
2C + O2
---------------- 2CO
Fe2O3 + 3CO --- 3CO2
+ 2Fe.
Role of Slag or Calcium
silicate : Lime stone dissociates in to
Cao which remove sand in the form of ( Calcium
silicate). It is interesting to note that
formation of calcium silicate not only removes
the sand rather protects the molten iron from
oxygen and avoid further oxidation of molten
iron.
Place of iron Extraction in
India : Jamshedpur, Rourkela, Bhilai,
Durgapur. |
Q.33. |
Which nutrient serves as a
ready source of energy in our body ? Write its
chemical formula Write down the balanced
equation for its complete oxidation . What test
will you perform for its presence in a food
sample ? Where is this nutrient stored in the
body when present in excess
? |
Ans. |
Nutrient -Glucose
is the nutrient which serves as a ready source
of energy in our body.
Test for Glucose -
Take some pieces of the given food sample and
crush them. Add few drops of Benedict's solution
to the crushed food sample in a test tube and
heat it. If the colour changes to red it shows
the presence of glucoose in the given food
sample.
Storage of Glucose in the
body - Excess amount of glucose is
stored in the liver in the form of Glycogen .
Excess amount of glucose is converted by Insulin
Harmone - secreted by pancreas, into glycogen
and slycogen stored in the liver is utilised by
the body later on for the production of energy
for body activities when ever we are on fast.
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